Radius of a circle with center O is 41 units. Length of a chord PQ is 80 units, find the distance of the chord from the center of the circle.

Given that
Radius = 41 units
So, OP = 41 units
And PQ = 80 units
We know that a perpendicular drawn from the center of a circle on its chord bisects
the chord.
∴ PM = MQ = 40 cm
In the right angled ΔOAP using Pythagoras theorem,
⇒ OP2 = OM2 + PM2
⇒ 412 = OM2 + 402
⇒ 1681 = OM2 + 1600
⇒ OM2 = 81
⇒ OM = 9 units
So, the distance of chord from the center is 9 units.
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