Q1 of 26 Page 82

Radius of circle is 10 cm. There are two chords of length 16 cm each. What will be the distance of these chords from the center of the circle?


Given radius of circle is 10cm


OA = OD = 10cm


AB = CD = 16cm


We know that a perpendicular drawn from the center of a circle on its chord bisects


the chord.


CQ = QD = 8cm


In right angled ΔOQD using the Pythagoras theorem


OD2 = OQ2 + QD2


102 = OQ2 + 82


100 = OQ2 + 64


OQ2 = 36


OQ = 6cm


Therefore the chord CD is at 6cm from the center.


We know that Congruent chords of a circle are equidistant from the center of the circle.


As AB and CD are equal in length, they are equidistant.


∴ OP = OQ = 6cm


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