Q1 of 26 Page 86

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Length of a chord of a circle is 24 cm. If distance of the chord from the center is 5 cm, then the radius of that circle is ….....


Given that OP = 5 cm


And AB = 24cm


We know that a perpendicular drawn from the center of a circle on its chord bisects


the chord.


∴ AP = PB = 12 cm


In the right angled ΔOAP using Pythagoras theorem,


⇒ OA2 = OP2 + AP2


⇒ OA2 = 52 + 122


⇒ OA2 = 25 + 144


⇒ OA2 = 169


⇒ OA = 13cm


Hence, The correct option is B.

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