Q3 of 23 Page 1

Solve Question:

Prove that, “If the angles of a triangle are 45°-45°-90°, then each of the perpendicular sides is times the hypotenuse.”


∠A = ∠C


AB = BC


∠B = 90°


⇒ By Pythagoras theorem


⇒ AC2 = AB2 + BC2


⇒ AC2 = 2AB2




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