Q3 of 23 Page 1

Solve Question:

Find the angle between two radii at the center of the circle as shown in the figure, Lines PA and PB are tangents to the circle at other ends of the radii and ∠APR = 110°.


∠APR = 110° - - given


∠APR + ∠BPA = 180°


∠APB = 180° - 110° = 70°


∠OAP = ∠OBP = 90°


Sum of angles of quadrilateral


∠APB + ∠OBP + ∠BPA + ∠OAP = 360°


70° + 90° + ∠AOB + 90° = 360°


∠AOB = 110°


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