Prove that the tangents to a circle at the end points of a diameter are parallel.

To prove: DE ∥ FG
Proof:
We know that tangent to a circle makes a right angle with the radius.
Let DE and FG be tangent at B and C respectively.
BC forms the diameter.
∴ ∠OBE = ∠OBD = ∠OCG = ∠OCF = 90°
Also, ∠OBD = ∠OCG and ∠OBE = ∠OCF as alternate angles
∴ DE and FG make 90° to same line BC which is the diameter.
Thus DE ∥ FG
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