Choose the correct answer and give justification for each.
In the figure XY and X1Y1 are two parallel tangents to a circle with centre O and another tangent AB with point of contact C intersecting XY at A and X1Y1 at B then ∠AOB =

A. 80o
B. 100o
C. 90o
D. 60o

Construct Line OC = radius
OP = OQ = OC = radius
OC∥AP and AC∥OP and
Thus AP = OP = radius
As AP = OP and ∠P = 90°
ΔOAP is isosceles triangle
∴ ∠ PAO = ∠POA = 45°
Also ∠ PAC = 90°
∠OAC = 45° ---1
Also AB is perpendicular to OC
∠OCA = 90°
In ΔAOC
∠OCA + ∠OAC + ∠COA = 180°
45 + 90 + ∠COA = 180°
∠COA = 45°
Similarly
∠BOC = 45°
∴ ∠AOB = 90°
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
