Q6 of 26 Page 242

In figure, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm., find the area of the shaded region.

(use π = 22/7)


Area of Shaded region = Area of sector OABC-Area of ΔDOB


OB = OA = 3.5cm






area of sector OABC = 9.625 cm2


Area of ΔDOB =


= 3.5 cm2


Area of Shaded region = 9.625-3.5


= 6.125 cm2


More from this chapter

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4

Find the area of the shaded region in figure, where ABCD is a square of side 10 cm. and semicircles are drawn with each side of the square as diameter

(use π = 3.14)


 5

Find the area of the shaded region in figure, if ABCD is a square of side 7 cm. and APD and BPC are semicircles.

(use π = 22/7)


 7

AB and CD are respectively arcs of two concentric circles of radii 21 cm. and 7 cm. with centre O (See figure). If ∠AOB = 30°, find the area of the shaded region.

(use π = 22/7)


 8

Calculate the area of the designed region in figure, common between the two quadrants of the circles of radius 10 cm. each.

(use π = 3.14)