Choose the correct answer and give justification for each.
If tangents PA and PB from a point P to a circle with centre O are inclined to each other at angle of 80o, then ∠POA is equal to
A. 50o
B. 60o
C. 70o
D. 80o

We know that tangent to a circle makes right angle with radius.
∴ ∠A = ∠B = 90° and ∠P = 80°
Sum of all angles of quadrilateral = 180°
∴ ∠A + ∠B + ∠P + ∠O = 360°
∴ 90° + 90° + 80° + ∠O = 360°
∠O = 100°
∠ AOP = ∠ BOP
∴ ∠POA = 50°
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