Q4 of 26 Page 242

Find the area of the shaded region in figure, where ABCD is a square of side 10 cm. and semicircles are drawn with each side of the square as diameter

(use π = 3.14)


Consider midpoint side AB, it forms Smaller square of size 5cm


For this smaller square


Area of shaded region


= Area of 1st quadrant + area of 2nd quadrant –area of square


Area of both quadrants is same


∴ Area of shaded region


= 2 × Area of quadrant - area of square


= 2 × – r × r


= 2 × – 5 × 5


= 2 × – 5 × 5


= 14.25 cm2


Area of total shaded region = 4 × 14.25


= 57 cm2


More from this chapter

All 26 →
2

A chord of a circle of radius 12 cm. subtends an angle of 120o at the centre. Find the area of the corresponding minor segment of the circle

(use π = 3.14 and √3 = 1.732)

 3

A car has two wipers which do not overlap. Each wiper has a blade of length 25 cm. sweeping through an angle of 115o. Find the total area cleaned at each sweep of the blades.

(use π = 22/7)

 5

Find the area of the shaded region in figure, if ABCD is a square of side 7 cm. and APD and BPC are semicircles.

(use π = 22/7)


 6

In figure, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm., find the area of the shaded region.

(use π = 22/7)