Q11 of 44 Page 79

Find the value of x in the following:

√3 tan 2x = sin 30° + sin 45° cos 45° + 2 sin 90°




sin90° = 1


∴sin 30° + sin 45° cos 45° + 2 sin 90°



= 3


∴tan 2x = sin 30° + sin 45° cos 45° + 2 sin 90°


⇒ √3tan2x = 3



⇒ tan2x = √3


But, tan60° = √3


⇒ tan2x = tan60°


⇒ 2x = 60°


⇒


⇒ x = 30°


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