Q13 of 44 Page 79

Prove that-

Cot45° = 1


∴ cot245° = 1


Sec60° = 2


∴ sec260° = 4




∴ LHS = 4cot245° - sec260° - sin230°





RHS =



∴ LHS = RHS


∴


Hence Proved


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√3 tan 2x = sin 30° + sin 45° cos 45° + 2 sin 90°

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sin 30° tan260° + 3cos 60° tan 45° = 2sec245° – cosec290°

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