Q14 of 44 Page 79

Prove that-

sin 30° tan260° + 3cos 60° tan 45° = 2sec245° – cosec290°






tan45° = 1


sec45° = √2


∴ sec245° = 2


cosec90° = 1


∴ cosec290° = 1


∴ LHS = sin30° tan260° + 3cos60°tan45°


=



RHS


2sec245° – cosec290°


= 2(2) – 1


= 3


RHS = LHS


Henc, Proved!


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