Q17 of 44 Page 79

Prove that-

2(cos245° + tan260°) – 6(sin245° – tan230°) = 6



tan60° = √3


∴ tan260° = 3






∴ LHS =




= 7 - 1


= 6


= RHS


∴ LHS = RHS


∴(cos245° + tan260°) – 6(sin245° – tan230°) = 6


Hence Proved


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