Q14 of 44 Page 80

Prove that 3(tan230° + cot230°) – 8(sin245° + cos230°) = 0



cot30° = √3


∴ cot230° = 3






∴ LHS =


3(tan230° + cot230°) – 8(sin245° + cos230°)




= 10 - 10


= 0


= RHS


∴ LHS = RHS


Hence Proved


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