Q16 of 44 Page 79

Prove that-



tan60° = √3


tan45° = 1


LHS =


(sin60° + sin30° )/(sin60° - sin30° )





RHS =


=



∴ LHS = RHS


∴


Hence Proved


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sin 30° tan260° + 3cos 60° tan 45° = 2sec245° – cosec290°

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Prove that-

2(cos245° + tan260°) – 6(sin245° – tan230°) = 6

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Prove that-

(sec230° + cosec245°) (2cos 60° + sin 90° + tan 45°) = 10