Q12 of 67 Page 187

The dimensions of a cuboid are in the ratio 5 : 3 : 2. If total surface area of the cuboid is 558 cm2, then find the length of edges of the cuboid.

Let


Length of cuboid = l = 5x


Breadth of cuboid = b = 3x


Height of cuboid = h = 2x


Such that the ratio is 5:3:2 as mentioned in question where x is any positive number


Total surface area of cuboid = 558 cm2


Total surface area of cuboid = 2 × (lb + bh + hl)


558 = 2 × [(5x)(3x) + (3x)(2x) + (2x)(5x)]


= 15x2 + 6x2 + 10x2


279 = 31x2


x2 =


x2 = 9


x = ± 3


x is length therefore x cannot be negative therefore x = 3


therefore,


length of cuboid = 5x = 5 × 3 = 15 cm


breadth of cuboid = 3x = 3 × 3 = 9 cm


height of cuboid = 2x = 2 × 3 = 6 cm


length of edges of cuboid are 15 cm, 9 cm and 6 cm


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