Q2 of 33 Page 95

In the picture of the parallelogram aside, let us calculate and write the value of ∠PRQ.

Given PQRS is Parallelogram


Each diagonal bisects the Parallelogram into two congruent triangles


And pair of opposite angles is equal


⇒∠PQR = ∠PSR = 55°


In ΔPSR


∠PSR = 55°, ∠SRP = 70°(given)


⇒ ∠RPS = 180° - (70° + 55°) = 180°- 125° = 55°(angle sum property of a triangle)
Now, PS ∥ QR and PR is transversal


So ∠SPR = ∠PRQ = 125° (alternate angles are equal on the transversal)


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