Q16 of 33 Page 108

In the parallelogram ABCD, ∠BAD = 75° and ∠CBD = 60°, then the value of ∠BDC is


In Parallelogram ABCD,


∠BAD = ∠BCD = 75° [Opposite angles of a parallelogram are equal]


In ΔBCD, By angle sum property


∠BCD + ∠BDC + ∠CBD = 180°


⇒ 75°+ ∠BDC + 60° = 180°


⇒ ∠BDC = 45°

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