Let us prove that in an isosceles trapezium the two angles adjacent to any parallel sides are equal.

Isosceles trapezium is a trapezium in which th non parallel sides are equal
Consider ABCD as the isosceles trapezium with AD = BC
We have to prove that ∠D = ∠C
Drop perpendiculars from point A and B on CD at points E and F respectively as shown
Consider ΔAED and ΔBFC
AD = BC … given … (i)
AE = BF … perpendiculars between two parallel lines … (ii)
Using Pythagoras theorem
DE2 =
and FC2 = ![]()
Using (i) and (ii)
⇒ DE2 = ![]()
⇒ DE2 = FC2
⇒ DE = FC … (iii)
Using (i), (ii) and (iii)
Therefore, ΔAED ≅ ΔBFC
⇒ ∠ADE = ∠BCF … corresponding angles of congruent triangles
⇒ ∠D = ∠C
Hence proved
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