Q16 of 33 Page 108

In the rhombus ABCD, ∠ACD = 40°, the value of ∠ADB is


In ΔCMD, By angle sum property


∠CMD + ∠MCD + ∠MDC = 180°


Now,


∠CMD = 90° [Diagonals of a rhombus bisect each other at right angles]


∠MCD = ∠ACD = 40° [Given]


∠MDC = ∠ADB [As diagonals bisect the angles in a rhombus]


⇒ 90° + 40° + ∠ADB = 180°


⇒ ∠ADB = 50°

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