Q15 of 56 Page 17

If the product of H.C.F and L.C.M of two natural numbers is 378000, then which of the following can be their H.C.F:

a) 66


b) 130


c) 34


d) 20

It is known that the H.C.F is a factor of L.C.M


So,


H.C.F must be a factor of 378000


After checking the options, 20 is the only number which can divide the product 37800 completely without leaving any remainder.


Hence 20 is the Solution.


More from this chapter

All 56 →
13

Can two numbers have H.C.F as 15 And L.C.M as 175? Give Reasons.

 14

In a 3-digit number unit's digit is one more than the hundred's digit and ten's digit is one less than the hundred's digit. If the sum of the original 3 - digit number and numbers obtained by changing the order of digits cyclically is 2664. Find the number.

 16

Find the H.C.F and L.C.M of 30, 72 and 432 by using Fundamental Theorem of Arithmetic.

 17

If d is the H.C.F of 30 and 72. Find the value of x and y satisfying d = 30x + 72y.