If p is a prime number then prove that √p is irrational.
let us suppose that
is a rational number.
then
where also a and b is rational and b ≠ 0
on squaring both sides,we get,
![]()
![]()

Let a = pr, for some integer r


![]()

Thus p is a common factor of a and b.
But this is a contradiction since a and b have no common factor as they are prime numbers
This is the contradiction to our assumption
Hence, √p is irrational.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.