Q16 of 56 Page 17

Find the H.C.F and L.C.M of 30, 72 and 432 by using Fundamental Theorem of Arithmetic.

For finding out H.C.F of 30,72 and 432, we would prime factorize the numbers separately

30 = 2 × 3 × 5


72 = 2 × 2 × 2 × 3 × 3


432 = 2 × 2 × 2 × 2 × 3 × 3 × 3


There H.C.F of 30, 72 and 432 is 2 × 3 = 6


L.C.M of 30, 72 and 432 is 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5 = 2160


H.C.F is 6 and L.C.M is 2160


More from this chapter

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14

In a 3-digit number unit's digit is one more than the hundred's digit and ten's digit is one less than the hundred's digit. If the sum of the original 3 - digit number and numbers obtained by changing the order of digits cyclically is 2664. Find the number.

 15

If the product of H.C.F and L.C.M of two natural numbers is 378000, then which of the following can be their H.C.F:

a) 66


b) 130


c) 34


d) 20

 17

If d is the H.C.F of 30 and 72. Find the value of x and y satisfying d = 30x + 72y.

 18

Find the H.C.F and L.C.M of 30, 72, 432 by using prime factorization method.