Show that there is no positive integer n so that
is rational.
Let us suppose there exist a positive integer for which
is a rational number, where p and q are positive and q ≠ 0
Rationalizing the RHS,

⇒
(∵ (a –b) (a +b) = a2 – b2)
![]()
Now ![]()
⇒
…… eq 2
Adding eq 1 and 2
![]()
⇒ ![]()
Hence there is no positive integer n for which
is a rational number
Couldn't generate an explanation.
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