Convert the following distribution into 'more than' frequency distribution and draw more than' ogive. Also find the median from it.


Now, taking lower class limits on x-axis and their respective frequencies on y-axis we can draw its ogive as follows:

Now, we have n = 201
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The cumulative Frequency just greater than
is 156 then the median class is 40 – 60 such that
the lower limit (l) = 40
cumulative frequency of the class preceding 40 - 60 (cf) = 92
frequency of the median class 40-60 = 64,
class size (h) = 20
Using the formula,
, we have
![]()
= 40 +2.65
= 42.65
= 42.7
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