Find the mean and median of the following data:


Now, ![]()
![]()
⇒x̄ = 45 + 5.44
⇒x̄ = 50.44

We have n = 250
So, ![]()
The cumulative Frequency just greater than
is 127 then the median class is 50-60 such that
the lower limit (l) = 50
cumulative frequency of the class preceding 50 – 60 (cf) = 96
frequency of the median class 50 – 60 = 31,
class size (h) = 10
Using the formula,
,we have
![]()
= 50 + 9.35
= 59.35
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