The median of the following data is 525. Find the values of x and y, if the total frequency is 100:

Given Median =525

Then, median Class = 500-600

the lower limit (l) = 500

cumulative frequency of the class preceding 500-600(cf) = 36 + x

frequency of the median class 500-600 = 20,

class size (h) = 100

Total frequencies (n) = 100

So, 76 + x + y = 100

⇒ x + y = 100 – 76

⇒ x + y = 24 …(i)

Using the formula,,we have

⇒25 = (14 – x) × 5

⇒5 = 14 – x

⇒ x = 9

Putting the value of x in eq. (i), we get

⇒ 9 + y = 24

⇒ y = 24 – 9

⇒ y = 15