Find the median from the following table:


We have n = 80
So, ![]()
The cumulative Frequency just greater than
is 56 then the median class is 40 – 50 such that
the lower limit (l) = 40
cumulative frequency of the class preceding 40 – 50 (cf) = 37
the frequency of the median class 40 – 50 =19,
class size (h) = 10
Using the formula,
, we have
![]()
= 40 + 1.58
=41.58
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