Q13 of 69 Page 7

Find the median from the following table:

Here, we can see that the intervals are unequal.


Firstly, we convert the unequal class intervals into equal class intervals.



We have n = 80


So,


The cumulative Frequency just greater than is 45 then the median class is 12-18 such that


the lower limit (l) = 12


cumulative frequency of the class preceding 12 – 18 (cf) = 17


frequency of the median class 12 – 18 = 28,


class size (h) = 6


Using the formula,,we have



= 12 + 4.928


= 14.93


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