Find the median of the following distribution:


We have n = 50
So, ![]()
The cumulative Frequency just greater than
is 36 then the median class is 10.75 – 11.25 such that
the lower limit (l) = 10.75
cumulative frequency of the class preceding 10.75 – 11.25 (cf) = 19
frequency of the median class 10.75 – 11.25 = 17,
class size (h) = 0.5
Using the formula,
, we have
![]()
= 10.75 + 0.176
= 10.93
Couldn't generate an explanation.
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