Prove the following by the principle of mathematical induction:

Let P(n): ![]()
For n = 1
P(1): ![]()
![]()
= P(n) is true for n = 1
Let P(n) is true for n = k, So
- - - - - (1)
Now, Let P(n) is true for n = k + 1, So
![]()
Then,
![]()
= ![]()
= ![]()
= ![]()
= ![]()
= ![]()
Therefore, P(n) is true for n = k + 1
Hence, P(n) is true for all n∈N
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.



