Prove the following by the principle of mathematical induction:


Let P(n): ![]()
Step 1: Let us check if P(1) is true or not,
P(1): ![]()
Therefore, P(1) is true.
Step 2: Let us assume that P(k) is true, now we have to prove that P(k + 1) is true.
P(k): ![]()
P(k+1): ![]()
From P(k) we can see that,
P(k + 1): ![]()
P(k + 1): ![]()
P(k + 1): ![]()
Therefore, P(k + 1) is true.
Hence, Proved by mathematical induction.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.




