Prove that
for all natural
numbers, n ≥ 2.
Let P(n) = ![]()
Let us find if it is true at n = 2,
P(2): ![]()
P(2): ![]()
Hence, P(2) holds.
Now let P(k) is true, and we have to prove that P(k + 1) is true.
Therefore, we need to prove that,
![]()
P(k) =
…….(1)
Taking L.H.S of P(k) we get,
P(k) = ![]()
P(k + 1) = ![]()
From equation (1),
P(k + 1) = ![]()
P(k + 1) = ![]()
P(k + 1) = ![]()
P(k + 1) = ![]()
Therefore, P(k + 1) holds.
Hence, P(n) is true for all n ≥ 2.
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