Given
and
for n ≥ 2, where a > 0, A > 0.
Prove that 
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Step1: For n=1


As LHS=RHS.
So, it is true for P(1)
For n=k, let P(k) be true.

Now, we need to show P(k+1) is true whenever P(k) is true.
P(k+1):







As L.H.S=R.H.S
Thus, P(k+1) is true. So, by the principle of mathematical induction
P(n) is true for all n.
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