The cost of 2 kg of apples and l kg of grapes on a day was found to be Rs 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs 300. Represent the situation algebraically and geometrically.
Let the cost of 1 kg of apple be x and cost of 1 kg of grape be y.
Given, cost of 2 kg of apples and l kg of grapes on a day was found to be Rs 160.
∴ 2x + y = 160
Also, after a month, the cost of 4 kg of apples and 2 kg of grapes is Rs 300.
∴ 4x + 2y = 300
Now to present these equations graphically plot the points of respective lines,
For 2x + y = 160,
y = 160 – 2x
When x = 50, y = 60
When x=60, y = 40
Table is:

Plot the points A(50,60) and B(60,40)
For 4x + 2y = 300,
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Plot the points C(40,–30) and D(60,30)

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