X takes 3 hours more than Y to walk 30 km. But if X doubles his pace, he is ahead of Y by 11/2 hours. Find their speed of walking.
Let the speed of X be x km/h and speed of Y is y km/h.
Time taken by X to cover distance of 30 km is
hrs.
Time taken by Y to cover distance of 30 km is
hrs.
As X takes 3 hours more than Y to walk 30 km,
So,
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…… (1)
Now if X doubles his place then time taken is
hrs
Time taken by Y to cover distance of 30 km is
hrs.
As if X doubles his pace, he is ahead of Y by 11/2 hours,
Also speed of X increases time taken by him will decrease.
So,
![]()
![]()
![]()
……. (2)
Now put ![]()
So (1) and (2) become,
10 u – 10v = 1
⇒ 10u – 10v – 1 = 0 ….. (3)
–10u + 20v = 1
⇒ –10u + 20v – 1 = 0 ….. (4)
Adding (3) and (4) we get,
10 u – 10 u – 10v + 20v – 1 – 1 = 0
⇒ 10 v – 2 = 0
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Put the value of v in (3) to get,
![]()
⇒ 10u – 2 – 1 = 0
⇒ 10u – 3= 0
![]()
Now ![]()
![]()
Hence speed of X and Y is
.
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