Three events A, B and C have probabilities
, respectively. Given that
and
, find the values of P (C | B) and P (A'∩ C').
GIVEN THAT
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AND,
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AND
By De Morgan’s laws:
(A ∪ B)’ = A’∩ B’ |
P (A'∩ C') = P(A Ս C)’
= 1- P (A Ս C)
= 1-[P(A)+ P(C)- P (A Ո C)]
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