Q61 of 108 Page 271

If P(A) = 0.4, P(B) = 0.8 and P(B | A) = 0.6, then P(A ∪ B) is equal to

We have,

P(A) = 0.4, P(B) = 0.8 and P(B|A) = 0.6


We know that,


P(B|A) × P(A) = P(B ∩ A)


⇒ 0.6 × 0.4 = P(B ∩ A)


⇒ P(B ∩ A) = 0.24


Now,


P(A ∪ B) = P(A) + P(B) – P(A ∩ B)


[Additive Law of Probability]


= 0.4 + 0.8 – 0.24


= 0.96


Hence, the correct option is D

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