Q64 of 108 Page 271

You are given that A and B are two events such that P(B)= 3|5, P(A | B) = 1|2 and P(A ∪ B) = 4|5, then P(A) equals

We have,


Now, We know that


P(A|B) × P(B) = P(A ∩ B)


[Property of conditional Probability]




Now,


P(A ∪ B) = P(A) + P(B) – P(A ∩ B)


[Additive Law of Probability]







Hence, the correct option is C

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62

If A and B are two events and A ≠ θ, B ≠ θ, then

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A and B are events such that P(A) = 0.4, P(B) = 0.3 and P(A ∪ B) = 0.5. Then P (B′ ∩ A) equals

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In Exercise 64 above, P(B | A′) is equal to

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If P(B) = 3|5, P(A|B) = 1|2 and P(A ∪ B) = 4|5, then P(A ∪ B)′ + P(A′ ∪ B) =