If A and B are two events such that
, the P(A′ ∩ B′) equals
We have,
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We know that,
P(A|B) × P(B) = P(A ∩ B)
[Property of Conditional Probability]
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Now, P(A’ ∩ B’) = 1 – P(A ∪ B)
= 1 – [P(A) + P(B) – P(A ∩ B)]
[∵P(A ∪ B) = P(A) + P(B) – P(A ∩ B)]
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Hence, the correct option is C
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