Q75 of 108 Page 271

Refer to Question 74 above. The probability that exactly two of the three balls were red, the first ball being red, is

A bag contains 5 red and 3 blue balls

Total Balls in a Bag = 8


For exactly 1 red ball probability should be


Now, 3 Balls are drawn randomly then possibility for getting 1 red ball


P(E)=P(R).P(B)+P(B).P(R)


P(E) =


Hence, P(E) = 4/7

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