Find the sum :
(CBSE 2013)
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a = 18, d =
- 18 = ![]()
Last term, an = ![]()
an = a+ (n – 1)d
= 18 + (n – 1) (
)
-99 = 36 + 5 – 5n
-140 = -5n
n = 28
S28=
[a + l]
= 14 (18 -
)
= 7 (36 – 99)
= 7 (-63) = -441
Couldn't generate an explanation.
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