If the sum of first n terms of an A.P. is
(3n2 + 7n), then find its nth term. Hence write its 20th term. (CBSE 2015)
Sn =
(3n2 + 7n)
First term, a = S1 =
[3(1)2 + 7(1)]
=
[3 + 7] = 5
S2 =
[3(2)2 + 7(2)]
a + a + d =
[12 + 14]
5 + 5 + d = 13
d = 3
an = a + (n – 1)d
= 5 + (n – 1) 3
= 5 + 3n – 3
= 3n + 2
a20 = 3(20) + 2
= 60 + 2 = 62
Hence, it’s 20th term is 62
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