Q18 of 45 Page 1

Solve the following differential equation:

ex tan y dx +(1 – ex) sec2 y dy = 0

ex tan y dx = - (1 – ex) sec2 y dy


ex tan y dx = (ex – 1) sec2 y dy



Integrating both the sides,



Putting & tan y = v


Differentiating u w.r.t. x & v w.r.t y








log u + C1 = log v



Putting C1= logC






is the general solution.


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