Q19 of 45 Page 1

If the function f (x) given by

is continuous at x =1, find the values of a and b.

To Find: Find the value of a and b?


For 3ax - b


where f(x) =3ax + b , then



…(i)


For 5ax - 2b


where f(x) =5ax - 2b , then



…(ii)


Now, It is given that


F(1)=11


Then,


3a + b=11


5a - 2b=11


Solve by elimination method


Multiply by 2 in equation (i) and Add with equation (ii)


6a + 2b=22


5a - 2b=11


Then


11a=33



a=3


putting the value of a in equation (i)


3(3) + b=11


9 + b=11


b=11 - 9


b=2


Hence, The value of a = 3 and b= 2


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