Find the value of a and b such that the following function f(x) is a continuous function:


Now,
F(x) is continuous at x=2
If L.H.L=R.H.L=f(2)
Then,
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L.H.L
![]()
5
R.H.L
![]()
![]()
2a + b
Since, L.H.L=R.H.L
2a + b=5 …(i)
Now,
F(x) is continuos at x=10
If L.H.L=R.H.L=f(10)
![]()
L.H.L
![]()
![]()
10a + b
R.H.L
![]()
21
Since, L.H.L=R.H.L
10a + b=21 …(ii)
Now, From (i) and (ii)
10a + (5 - 2a)=21
8a=16
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a=2
Putting the value of a in equation (i)
2(2) + b=5
4 + b=5
B=5 - 4
b=1
Hence, The value of a = 2 and b=1
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