Form the differential equation of the family of parabolas having vertex at the origin and axis along positive y–axis.
When the vertices of parabola at origin and axis along positive y - axis
Then, Equation of parabola is
x2=4ay …(i)
Now, Differentiate equation (i) w.r.t x
![]()
![]()
![]()
x=2ay’ …(ii)
Now, Divide equation (ii) by (i) , we get
![]()
![]()
2y=xy’
xy’ - 2y=0
Hence, The required differential equation is xy’ - 2y=0
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.


