Using properties of determinants, prove the following:

Given, 
Taking xyz as common from C1C2C3 , then

Applying C1→ C1 - C2 , C2→C2 - C3, then,

Taking (x - y)(y - z) as common from C1 and C2

Now, Expand along R1 , then

= xyz(x - y)(y - z)(z - x)
Hence, Proved
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