Evaluate: 
OR
Evaluate:
Let 
Sin x = t cos x dx = dt

Using integration by parts,
![]()
{limits are 0 to 1}
![]()
![]()
![]()
Hence the required value is ![]()
OR
Let I = 
Here, the
denotes 90![]()


Adding both the above-mentioned equations,


Putting sin2x =t
2 sinx . cos x dx = dt
![]()
As x
to 0, t
to 0
As x
to 90, t
to 1





![]()
Limits are 0 to 1.
![]()
![]()
![]()
![]()
Hence the required integrated value is
.
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